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ELIGIBILITY FOR IIT JEE 2018

All the candidates must fullfil  each and every one of the following five criteria to appear in JEE (Advanced) 2018. Criterion 1 – Performance in JEE (Main) 2018 : Candidates should be among the top 2,24,000* (including all categories) in Paper-1 of JEE (Main) 2018. The percentages of various categories of candidates to be shortlisted are: 27% for OBC-NCL, 15% for SC, 7.5% for ST and the remaining 50.5% is OPEN for all. Within each of these four categories, 5% horizontal reservation is available for PwD candidates. The following table shows the order to be followed while choosing top 2,24,000* candidates in various categories based on the performance in Paper-1 of JEE (Main) 2018. Category-wise distribution of top 2,24,000* candidates (Criterion 1) ORDER CATEGORY Number of “Top” candidates 1 OPEN 1,07,464 Total 1,13,120 2 OPEN-PwD 5,656 3 OBC-NCL 57,456 Total 60,480 4 OBC-NCL-PwD 3,024 5 SC 31,920 Total 33,600 6 SC-PwD 1,680 7 ST 15,960 T
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Reason of Magnetism

Magnetism is the force exerted by magnets when they attractor repel each other. Magnetism is caused by the motion of electric charges. Every substance is made up of tiny units called atoms. Each atom has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the nucleus, or core, of an atom. Their movement generates an electric current and causes each electron to act like a microscopic magnet. In most substances, equal numbers of electrons spin in opposite directions, which cancels out their magnetism. That is why materials such as cloth or paper are said to be weakly magnetic. In substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. This makes the atoms in these substances strongly magnetic—but they are not yet magnets. To become magnetized, another strongly magnetic substance must enter the magnetic field of an existing magnet. The magnetic field is the area around a magnet that has magnetic force.  All
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TARGET NTSE Stage II

Pattern and Syllabus for NTSE Stage II NTSE Stage-II question paper is divided into 3 sections to attempt. The paper has 200 multiple choice objective type questions of total 200 marks, 1 mark will be awarded for each correct answer and 1/3 marks will be deducted for each wrong answer. No marks will be awarded or deducted for the unanswered questions. Test No. of questions Marks Duration Mental Ability Test (MAT) 50 50 45 mins Language Test (English/ Hindi) 50 50 45 mins Scholastic Ability Test (SAT) 100 100 90 mins The syllabus of NTSE Stage-II is similar to the syllabus of Class X as prescribed by CBSE. Candidates must consider the NCERT books of Class XI and X for the detailed syllabus. The detailed syllabus for Mathematics, Social Science and Science is mentioned below. The syllabus strictly refers to the NCERT syllabus of Class X textbooks. Mathematics Social Science Science Arithmetic Popular Movements and Social Reforms Acid Bases and Salt Algebraic Expressions
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Systematic Revision Plan

Clearing #JEE (Main) is not a difficult task. Systematic approach towards its preparation alongwith a proper revision plan will help students get admission into one of the IIT's & Top National Institutes of Technology (NIT's). 1. Identify the topics subject wise you have difficulties in remembering the formulae of solving questions 2. Take up previous year #JEE Papers or question banks of reputed sources of these topics and solve them in a planned manner so that you can practice as much as possible in the gaps available between the Board Exam. E.g: the gap before Physics should be utilised for solving questions of topics in Physics so that your flow of preparation for boards does not get disturbed. 3. Keep a check on your problem-solving ability as spending too much time on a question you do not know will result in loss of adequate time for the easier ones. 4.Taking Mock Test and having a real time analysis have been found to be quite useful and students tend to learn f
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Better Begun is Half Done

A serious aspirant ideally must have completed the syllabus by now. The following three points now will ensure your success in JEE: 1. Time Management 2. Exam Strategy 3. Complete coverage of syllabi and a systematic revision plan Few of the tips listed below will be of help: In this last one month for students who are taking up Board Exams this time should be essentially used for taking up Mock Tests on lines of JEE(Main) & JEE(Advanced). Analysis of each paper is important to check the mistakes and to avoid repeating them in the actual JEE. The time gap between the Board Exams should be smartly utilised subject wise catering to the needs of both Boards and Entrance Exams. For students who are repeaters, may join a crash course for topic wise revision along with several Mock Tests on current pattern of JEE, else they should have a systematic revision plan involving rigorous testing conceptwise/chapterwise along with several mock Tests from reliable sources as per current patt
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Rolling Motion made Easy

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Q. Many of us we think that Rolling Motion is tough? The answer to the above question is "BIG NO" things are only tough till you understand them completely. So, I am here to guide you on the above topic. Leave comments on any Doubts faced by you recently. When we talk about pure Rotational Motion we imagine a fixed axis about which the all the particles of the Rigid Body are moving in a Circular Motion. Hence if the body moves with angular Velocity ' omega ' (w) than every particle on the periphery will have linear velocity as v =wr ( where r is the radius of the particle from its axis ). In the above Diagram we see 3 figures: 1st figure shows when the body is in pure translational motion only, every particle of the rigid body will have same velocity ( same Direction ) as visible. 2nd figure shows when the body is in pure rotational motion as discussed above particle will have same speed but different velocity about fixed axis O. 3rd figure sh
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WORK, ENERGY & THEOREM

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Q1 . A cyclist and his bicycle has a mass of 80 kg. After 100m he reaches the top of a hill, with slope 1 in 20 measured along the slope, at a speed of 2 m/s. He then free wheels the 100m to the bottom of the hill where his speed has increased to 9m/s. How much energy has he lost on the hill? Solution Figure 3.3: Dimensions of the hill in worked example 3.5 If the hill is 100m long then the height is: So potential energy lost is Increase in kinetic energy is By the principle of conservation of energy
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